Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Section 7.1 - Inverse Functions and Their Derivatives - Exercises 7.1 - Page 372: 18

Answer

$ a.\quad$The graph is symmetric about the origin. $b.\quad f(x)=f^{-1}(x)$

Work Step by Step

$a.$ See graph. The graph is symmetric about the origin. $b.$ Solve the equation for x, writing $y=f(x)$ $ y=\displaystyle \frac{1}{x} \qquad$... raise both sides to $(...)^{-1}$ $\displaystyle \frac{1}{y}=x\qquad$... interchange $x\leftrightarrow y$ $y=f^{-1}(x)=\displaystyle \frac{1}{x}=f(x)$
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