Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Section 7.1 - Inverse Functions and Their Derivatives - Exercises 7.1 - Page 372: 16

Answer

Domain of $f^{-1}$ = range of $f$ = $(-2,1]$ Range of $f^{-1}$ = domain of $f$ = $[-1,3)$

Work Step by Step

Follow the instructions: 1. Draw a line through (0,0) and ($3,3$): $y=x$. 2. Select endpoints from the graph of f, and reflect them across $y=x.$ 3. Join the new points with line segments: graph of $f^{-1}(x)$ Domain of $f^{-1}$ = range of $f$ = $(-2,1]$ Range of $f^{-1}$ = domain of $f$ = $[-1,3)$
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