#### Answer

$8 \pi $

#### Work Step by Step

We integrate the integral as follows:
$V= \int_{0}^{2} (\dfrac{5\pi y^4}{4}) \cdot y^4 dy$
Now, $V= (\dfrac{5\pi}{4}) \times [(\dfrac{y^5}{5})]_{0}^{2}$
or, $= (\dfrac{5\pi}{4}) \times (\dfrac{32}{5})$
or, $=8 \pi $