Answer
=$\frac{16}{3}$
Work Step by Step
A(x)=$(edge)^2$
= $[\sqrt{ 1-x^2} - (-\sqrt {1-x^2})]^2 $
=$(2\sqrt {1-x^2})^2$
=$4(1-x^2)$; a=-1, b=1;
V=$\int^b_a A(x) dx $
= $\int^1_{-1} 4 (1-x^2)dx$
=$4[x-\frac{x^3}{3}]^1_{-1}$
=$8(1-\frac{1}{3})$
=$\frac{16}{3}$
