Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.4 - Concavity and Curve Sketching - Exercises 4.4 - Page 215: 103

Answer

$f(x)=\ln x$ is such a function. $f$ is concave down on $(0,\infty).$

Work Step by Step

$\ln x$ is such a function. $\displaystyle \frac{d}{dx}(\ln x)=\frac{1}{x}$ and $\ln 1=0.$ If $f'(x)=\displaystyle \frac{1}{x}=x^{-1}$, then, $f''(x)=-x^{-2}$, which is negative for $x\gt 0$. This means that the graph is concave down on $(0,\infty).$
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