Answer
Does not satisfy
Work Step by Step
Since, we have, $f(x)=x^{\frac{2}[3}$
Also, $f'(x)=\dfrac{2}{3x^{1/3}}$ .
This implies that the function is undefined at $x=0$. So, this is not differentiable at $x=0$.
Hence, The Mean value Theorem does not satisfy.