Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Practice Exercises - Page 243: 7

Answer

NO

Work Step by Step

Because the function is not continuous. watch out the situation when x = 0 or 1, being continuous meaning be defined at these point.
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