Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.8 - Related Rates - Exercises 3.8 - Page 162: 14

Answer

a) ${\frac{dV}{dt}}={\frac{1}{3}\pi r^2 \frac{dh}{dt}}$; b) ${\frac{dV}{dt}}={\frac{2}{3}\pi r h \frac{dr}{dt}}$; and c) ${\frac{dV}{dt}}={\frac{1}{3}\pi r^2 \frac{dh}{dt}}+{\frac{2}{3}\pi r h \frac{dr}{dt}}$

Work Step by Step

Volume of a hemisphere $V={\frac{1}{3}\pi r^2 h}$ a) Radius as constant and height is changing, then ${\dfrac{dV}{dt}}={\dfrac{1}{3}\pi r^2 (\dfrac{dh}{dt}})$ b) When height is constant and radius is changing, then ${\dfrac{dV}{dt}}={\dfrac{2}{3}\pi r h (\dfrac{dr}{dt}})$ c) When radius is changing and height is changing, then ${\dfrac{dV}{dt}}={\dfrac{1}{3}\pi r^2 (\dfrac{dh}{dt}})+{\dfrac{2}{3}\pi r h (\dfrac{dr}{dt}})$
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