Answer
$-1$
Work Step by Step
$\lim_{x\to0}sec[cos(x)+\pi tan\frac{\pi}{4sec(x)}-1]=sec[cos(0)+\pi tan\frac{\pi}{4sec(0)}-1]=
sec[1+\pi tan\frac{\pi}{4}-1]=sec[\pi]=-1$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.5 - Derivatives of Trigonometric Functions - Exercises 3.5 - Page 142: 51
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