Answer
$0$
Work Step by Step
$\lim_{x\to2}sin(\frac{1}{x}-\frac{1}{2})=\lim_{x\to2}sin(\frac{2-x}{2x})=sin(\frac{2-2}{2(2)})=sin(0)=0$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.5 - Derivatives of Trigonometric Functions - Exercises 3.5 - Page 142: 47
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