#### Answer

First Derivative: $y'=12x-10+10x^{-3}$
Second Derivative: $y''=12-30x^{-4}$

#### Work Step by Step

Using the Power Rule:
First Derivative:
$y=6x^{2}-10x-5x^{-2}$
$y'=(2)(6)x^{2-1}-(1)(10)x^{1-1}-(-2)(5)x^{-2-1}$
$y'=12x-10+10x^{-3}$
Second Derivative
$y'=12x-10+10x^{-3}$
$y''=(1)(12)x^{1-1}-(0)+(-3)(10)x^{-3-1}$
$y''=12-30x^{-4}$
(the derivative of 10 will be 0 because of the rule of the constant function)