## Thomas' Calculus 13th Edition

First Derivative: $y'=-2+3x^{-4}$ Second Derivative: $y''=-12x^{-5}$
Using the Power Rule: First Derivative: $y=4-2x-x^{-3}$ $y'=(0)-(1)(2)x^{1-1}-(-3)x^{-3-1}$ $y'=-2+3x^{-4}$ (the derivative of 4 will be 0 because of the rule of the constant function) Second Derivative: $y'=-2+3x^{-4}$ $y''=-(0)+(-4)(3)x^{-4-1}$ $y''=-12x^{-5}$ (the derivative of 2 will be 0 because of the rule of the constant function)