#### Answer

First Derivative: $y'=-2+3x^{-4}$
Second Derivative: $y''=-12x^{-5}$

#### Work Step by Step

Using the Power Rule:
First Derivative:
$y=4-2x-x^{-3}$
$y'=(0)-(1)(2)x^{1-1}-(-3)x^{-3-1}$
$y'=-2+3x^{-4}$
(the derivative of 4 will be 0 because of the rule of the constant function)
Second Derivative:
$y'=-2+3x^{-4}$
$y''=-(0)+(-4)(3)x^{-4-1}$
$y''=-12x^{-5}$
(the derivative of 2 will be 0 because of the rule of the constant function)