Answer
$6$
Work Step by Step
Use derivative formula; $f(x)= x^n \implies f'(x)= n x^{n-1}$
Consider $s(t) = 1-3t^{2}$
Thus, $s'(t) = 0 - 3(2)t^{2-1}= -6t$
and $s'(-1) = -6(-1)=6$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.2 - The Derivative as a Function - Exercises 3.2 - Page 115: 19
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