Answer
$23.53\leq R \leq 24.48$ ohms
Work Step by Step
Step 1. Identify the given conditions: $V=RI, V=120V, I_0=5A, I=I_0\pm 0.1A$; we need to find an interval for the resistance $R$ so that the current $I$ satisfy the given range.
Step 2. Rewrite the equation as $I=\frac{V}{R}$; we have $|I-I_0|\leq0.1$ or $|\frac{V}{R}-5|\leq0.1$
Step 3. Evaluate the inequality: $-0.1\leq \frac{V}{R}-5 \leq 0.1$ or $4.9\leq \frac{V}{R} \leq 5.1$
Step 4. Use the value $V=120$ to get $\frac{4.9}{120}\leq \frac{1}{R} \leq \frac{5.1}{120}$ or $ \frac{120}{5.1} \leq R \leq \frac{120}{4.9}$
Step 5. Approximate the values: $\frac{120}{5.1}\approx23.5294 $ and $\frac{120}{4.9}\approx24.4898$
Step 6. Thus we can safely conclude that $23.53\leq R \leq 24.48$ ohms
