Answer
a) $1$
b) $0$
c) $\dfrac{16}{3}$
Work Step by Step
a) $\lim\limits_{x \to -2}(p(x)+r(x)+s(x)) = 4+0-3 =4-3= 1$
b) $\lim\limits_{x \to -2}p(x).r(x).s(x) =( 4)(0)(-3) = 0$
c) $\lim\limits_{x \to -2}\dfrac{(-4)p(x)+(5)r(x)}{s(x)} = \dfrac{(-4)(4)+(5)(0)}{-3}=\dfrac{16}{3}$
