## Thomas' Calculus 13th Edition

$-1$
Note that, $\lim\limits_{x \to a}\cos x=\cos a$ for all real numbers $a$. Using this along with our limit laws, we get $\lim\limits_{x \to 0}[(x^2-1)(2-\cos x)]=(0-1)(2-\cos 0)=(-1)(2-1)=(-1)(1)=-1.$