## Thomas' Calculus 13th Edition

Published by Pearson

# Chapter 16: Integrals and Vector Fields - Section 16.1 - Line Integrals - Exercises 16.1 - Page 943: 4

Graph(a)

#### Work Step by Step

Given: $r(t)=ti$ and $-1 \lt t \lt 1$ This represents any point on the graph having the form of $(t,0,0)$ . Here,the $y$ and $z$ intercepts are both $0$. The value of $x$ is in between $-1$ to $+1$ which makes a line segment along $x$-axis. The answer is: Graph(a).

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