Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 16: Integrals and Vector Fields - Section 16.1 - Line Integrals - Exercises 16.1 - Page 943: 1

Answer

Graph(c)

Work Step by Step

Given: $x=t,y=1-t, z=0$ and $x+y=1$ and $z=0$ Here, the $x$ and $y$- intercepts are both $1$ and represents a line segment joining $(1,0,0),(0,1,0)$.Thus, the answer is Graph(c).
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