## Thomas' Calculus 13th Edition

$\int^1_0 \int^1_0 \int^1_{x^2} 12xze^{zy^2}$ dy dx dz =$\int^1_0 \int^1_0 \int^\sqrt{y}_0 12xz e^{zy^2}$ dx dy dz =$\int^1_0 \int^1_0 6yz e^{zy^2}$ dy dz =$\int^1_0 [3e^{zy^2}]^1_0 dz$ =$3\int^1_0 (e^z-1)dz$ =$3[e^z-z]^1_0$ =$3e-6$