Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Section 15.4 - Double Integrals in Polar Form - Exercises 15.4 - Page 892: 3

Answer

-$\frac{\pi}{4}\leq \Theta \leq \frac{3\pi}{4} $ ,$0\leq r \leq cos\Theta$

Work Step by Step

Describing the given region in polar coordinates of the below graph y=x=>$\Theta=\frac{\pi}{4},y=-x=>\Theta$ $=\frac{3\pi}{4}.y=1=>cos \Theta$ -$\frac{\pi}{4}\leq \Theta \leq \frac{3\pi}{4} $ ,$0\leq r \leq cos\Theta$
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