## Thomas' Calculus 13th Edition

-$\frac{\pi}{2}\leq \Theta \leq \frac{\pi}{2}$ ,$1\leq r \leq 4$
Describing the given region in polar cordinates of the given graph $x^2+y^2=1^2$ => $r=1$ $x^2+y^2=4^2$ $r=4$ =-$\frac{\pi}{2}\leq \Theta \leq \frac{\pi}{2}$ ,$1\leq r \leq 4$