## Thomas' Calculus 13th Edition

Published by Pearson

# Chapter 15: Multiple Integrals - Section 15.4 - Double Integrals in Polar Form - Exercises 15.4 - Page 892: 2

#### Answer

-$\frac{\pi}{2}\leq \Theta \leq \frac{\pi}{2}$ ,$1\leq r \leq 4$

#### Work Step by Step

Describing the given region in polar cordinates of the given graph $x^2+y^2=1^2$ => $r=1$ $x^2+y^2=4^2$ $r=4$ =-$\frac{\pi}{2}\leq \Theta \leq \frac{\pi}{2}$ ,$1\leq r \leq 4$

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