Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Section 15.2 - Double Integrals over General Regions - Exercises 15.2 - Page 883: 65

Answer

$2+2 \ln (2)$

Work Step by Step

Consider $I= \iint_{R} f(x,y) dA$ or, $= \int_{1}^{2} \int_{-1/x}^{1/x} (x+1) dy dx$ or, $= \int_{1}^{2}[\dfrac{x^2}{2}+x]_{-1/x}^{1/x} dx$ or, $=\int_{1}^{2} 2+\dfrac{2}{x} dx$ Thus, we have $I=2x+2 \ln x]_1^2=2+2 \ln (2)$
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