Answer
$M=3 \delta$
$I_x=2 \delta$
Work Step by Step
$$M= \delta \int_{0}^{3} \int_{0}^{2x/3} \ dy \ dx \\= \delta \int_{0}^{3} \dfrac{2}{3} \times x \ dy \ dx \\= 3 \delta \\I_x= \delta \int_{0}^{3} \int_{0}^{2x/3} y^2 \ dy \ dx \\= \int_{0}^{3} \dfrac{8 x^3 \delta}{81} \ dx \\=(\dfrac{8 \delta}{81}) (\dfrac{3^4}{4})=2\delta $$
