Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Practice Exercises - Page 933: 10



Work Step by Step

We calculate the integral as follows: $$\int_{0}^{2} \int_{y/2}^{1} e^{x^2} \ dx \ dy \\=\int_{0}^{1} \int_{0}^{2x} e^{ x^2} \ dy \ dx \\= 2 \int_{0}^{1} x \times e^{x^2} \ dx \\=[e^{x^2}]_0^1 \\=e^{1}-e^0 \\=e-1$$
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