Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 13: Vector-Valued Functions and Motion in Space - Section 13.1 - Curves in Space and Their Tangents - Exercises 13.1 - Page 747: 34

Answer

$0$

Work Step by Step

Let us Consider, $c(t)=\lt c_1, c_2, c_3 \gt$ Here, $c_1, c_2, c_3$ refers to constants Since, $u=c $ and $\dfrac{d}{dt}(u)=\dfrac{d}{dt}c$ Thus, we have $u'=\lt \dfrac{d}{dt}(c_1), \dfrac{d}{dt}(c_2), \dfrac{d}{dt}(c_3) \gt$ so, $u'=\lt 0,0,0 \gt =0$
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