Answer
$\dfrac{1}{2}$
Work Step by Step
Here, we have $\dfrac{dx}{dt}=2(x-t)$
and $\dfrac{dy}{dt}=(e^t)(t+1)$
Here, $x-t=1$ when $t=0$
$\implies \dfrac{dx}{dt}=2$
Also, $ \dfrac{dx}{dt}(t=0)=1$
Thus,
Slope: $\dfrac{dy}{dx}=\dfrac{(e^{0})(0+1)}{2(1)}=\dfrac{1}{2}$