Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 11: Parametric Equations and Polar Coordinates - Practice Exercises - Page 688: 29


A circle with center $(0,-2)$ and radius $2$

Work Step by Step

Consider $r=-4\sin \theta$ or, $r^2=-4r \sin \theta$ This implies that $x^2+y^2+4y=0$ This can be re-arranged as: $x^2+(y+4)^2=16$ Hence, we get the equation of a circle with center $(0,-2)$ and radius $2$
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