Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 11: Parametric Equations and Polar Coordinates - Practice Exercises - Page 688: 27

Answer

$y=\dfrac{-3}{2}$

Work Step by Step

Consider $r=\dfrac{-3}{2}\csc \theta$ This can be re-arranged as: $r \sin \theta =\dfrac{-3}{2}$ This implies that $y=\dfrac{-3}{2}$
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