Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.9 - Convergence of Taylor Series - Exercises 10.9 - Page 625: 40

Answer

$\space |\space Error| \lt 1.25 \times 10^{-5}$

Work Step by Step

Recall the Binomial series for $\sqrt{1+x}=1+\dfrac{x}{2}-\dfrac{x^2}{8}+\dfrac{x^3}{16}-.....$ By the Alternating Series Estimation Theorem, the error can be computed as: $|Error| \lt |\dfrac{-x^2}{8}| $ $\implies \space |Error| \lt \dfrac{(0.01)^2}{8} $ Thus, $\space \implies |\space Error| \lt 1.25 \times 10^{-5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.