Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Practice Exercises - Page 637: 90

Answer

It converges by the Limit Comparison Test

Work Step by Step

It converges by the Limit Comparison Test Since $\lim\limits_{n \to \infty}\frac{\frac{a_{n}}{1+a_{n}}}{a_{n}}=\lim\limits_{n \to \infty}\frac{1}{1+a_{n}}=1$ because $\Sigma$ $a_{n}$ converges and so $a_{n} -> 0$
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