Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Practice Exercises - Page 637: 82

Answer

The radius of convergence is equal to: $\dfrac{5}{2}$

Work Step by Step

Apply the Ratio Test to the series as follows: $$\lim\limits_{n \to \infty} |\dfrac{u_{n+1}}{u_n}|=\lim\limits_{n \to \infty} |\dfrac{(2n+3) (x-1)}{5n+4}| \\=|x-1| \times \lim\limits_{n \to \infty} (\dfrac{(2n+3)}{5n+4}) \\=\dfrac{2}{5}|x-1|$$ But the series is absolutely convergent for $\dfrac{2}{5}|x-1| \lt 1 \implies |x-1| \lt \dfrac{5}{2}$ Thus, the radius of convergence is equal to: $\dfrac{5}{2}$
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