## Thomas' Calculus 13th Edition

Published by Pearson

# Chapter 1: Functions - Section 1.2 - Combining Functions; Shifting and Scaling Graphs - Exercises 1.2: 44

#### Answer

The picture is provided below.

#### Work Step by Step

You draw it like you would draw $y=x^{2/3}$, except that you use $(0, -4)$ instead of $(0,0)$ as the starting point. (If you do not recall the shape of $y=x^{2/3}$ since it is a fairly uncommon graph, plot a few points of the function in order to determine the overall shape.)

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