## Thomas' Calculus 13th Edition

(a). $-x$, $[-2,\infty)$, $(-\infty, 2]$ (b). $\sqrt {4-x^2}$, $[-2,2]$, $[0, 2]$
(a). $f(g(x))=2-(x+2)=-x$ Domain: $[-2,\infty)$ Range: $(-\infty, 2]$ (b). $g(f(x))=\sqrt {2-x^2+2}=\sqrt {4-x^2}$ Domain: $[-2,2]$ Range: $[0, 2]$