Answer
a. $1$
b. $\sqrt {2/5}$
c. $ x $
d. $\frac{1}{\sqrt {1/\sqrt {x+2}+2}}$
Work Step by Step
a. $ g(-1)=1,f(g(-1))=f(1)=1$
b. $ f(2)=1/2, g(1/2=\sqrt {2/5})$
c. $ f(f(x))=\frac{1}{1/x}=x $
d. $ g(g(x))=\frac{1}{\sqrt {1/\sqrt {x+2}+2}}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 1: Functions - Practice Exercises - Page 37: 35
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