## Thomas' Calculus 13th Edition

a. $1$ b. $\sqrt {2/5}$ c. $x$ d. $\frac{1}{\sqrt {1/\sqrt {x+2}+2}}$
a. $g(-1)=1,f(g(-1))=f(1)=1$ b. $f(2)=1/2, g(1/2=\sqrt {2/5})$ c. $f(f(x))=\frac{1}{1/x}=x$ d. $g(g(x))=\frac{1}{\sqrt {1/\sqrt {x+2}+2}}$