Answer
{$-\frac{1}{2},\frac{2}{3},-\frac{3}{7},\frac{4}{25},-\frac{5}{121}$}
Work Step by Step
$a_{n}=\frac{(-1)^{n}n}{n!+1}$
$a_{1}=\frac{(-1)^{1}1}{1!+1}=-\frac{1}{2}$
$a_{2}=\frac{(-1)^{2}2}{2!+1}=\frac{2}{3}$
$a_{3}=\frac{(-1)^{3}3}{3!+1}=-\frac{3}{7}$
$a_{4}=\frac{(-1)^{4}4}{4!+1}=\frac{4}{25}$
$a_{5}=\frac{(-1)^{5}5}{5!+1}=-\frac{5}{121}$
