Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - 11.1 Exercises - Page 724: 31



Work Step by Step

Since the highest degree of $n$ in the numerator is 2 and the highest degree in the denominator is 3/2, the limit as $n$ approaches infinity will be that of $\frac{n^2}{n^{3/2}} = \sqrt{n}$. Hence the sequence diverges.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.