Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - 11.1 Exercises - Page 724: 17

Answer

$a_{n}=(-1)^{n+1}\times\frac{n^{2}}{n+1}$

Work Step by Step

{${\frac{1}{2}, -\frac{4}{3}, \frac{9}{4}, -\frac{16}{5}, \frac{25}{6}}$} The first few terms switch between positive and negative so, $a_{n}=(-1)^{n+1}$ We then notice that the numerator exponentially increases as the denominator increases by one each term. Numerator: ${n^{2}}$ Denominator: $n+1$ Combine all three equations and we get, $a_{n}=(-1)^{n+1}\times\frac{n^{2}}{n+1}$
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