Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Appendix G - Exercises - Page A12: 3

Answer

$13+18i$

Work Step by Step

Given: $(2+5i)(4-i)$ $=2(4)+2(-i)+(5i)(4)+(5i)(-i)$ $=8-2i+20i-5i^{2}$ Since, $i^2=-1$ and $i=\sqrt{-1}$ Thus, $=8+18i-5*-1$ $=8+18i+5$ $=13+18i$
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