Answer
$1$
Work Step by Step
Given: $e^{2\pi i}$
To write the number as $a+bi$, we apply Euler's formula, $e^{iy}=\cos{y}+i\sin{y}$
$e^{2\pi i}=\cos 2\pi+i\sin 2\pi$
$=1+i \times 0$
$=1$
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