Answer
a) $4\sqrt 2 [\cos (31\pi/12)+i \sin (31\pi/12)]$
b) $2 \sqrt 2 [\cos (13\pi/12)+i \sin (13\pi/12)]$
c) $\dfrac{1}{4}[\cos (-11\pi/6)+i \sin (-11\pi/6)]$
(Note that other angles are possible if simplified or rewritten.)
Work Step by Step
Here, $z=4 [\cos (11\pi/6)+i \sin (11\pi/6)]; w=\sqrt 2 [\cos (3\pi/4)+i \sin (3\pi/4)]$
a) $zw=4 [\cos (11\pi/6)+i \sin (11\pi/6)] \times \sqrt 2 [\cos (3\pi/4)+i \sin (3\pi/4)]=4\sqrt 2 [\cos (31\pi/12)+i \sin (31\pi/12)]$
b) $\dfrac{z}{w}=\dfrac{4 [\cos (11\pi/6)+i \sin (11\pi/6)]}{\sqrt 2 [\cos (3\pi/4)+i \sin (3\pi/4)]}=2 \sqrt 2 [\cos (13\pi/12)+i \sin (13\pi/12)]$
c) $\dfrac{1}{z}=\dfrac{1}{4 [\cos (11\pi/6)+i \sin (11\pi/6)]}=\dfrac{1}{4}[\cos (-11\pi/6)+i \sin (-11\pi/6)]$
