Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.3 - Logarithmic Functions and Models - Exercises - Page 660: 80

Answer

$\displaystyle \frac{1}{2}\ln a$

Work Step by Step

Expressing the root with a rational exponent $\sqrt{a}=a^{1/2}$ We get: $\ln\sqrt{a}=\ln a^{1/2}$ Apply the rule: $\log_{b}\left(x^{r}\right)=r\log_{b}x$ We get: $=\displaystyle \frac{1}{2}\ln a$
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