Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.3 - Logarithmic Functions and Models - Exercises - Page 660: 77

Answer

$8$

Work Step by Step

First, we simplify $\log_{2}8$ by recognizing that $8=2^{3}$: $\log_{2}8=\log_{2}2^{3}$ Apply the rule $\log_{b}\left( b^{x} \right)=x$ We get: $\log_{2}8=3$ So, $2^{\log_{2}8}=2^{3}=8$
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