Answer
$10^{-5}$ moles
Work Step by Step
If $p_{H}=-\log H^{+}$, then
$\log H^{+}=-p_{H}$
$H^{+}=10^{-p_{H}}$
So, for $p_{H}=5.0,$
$H^{+}=10^{-5.0}=0.00001=10^{-5}$ moles
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 9 - Section 9.3 - Logarithmic Functions and Models - Exercises - Page 660: 68b
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
