Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 14 - Section 14.6 - Differential Equations and Applications - Exercises - Page 1068: 5

Answer

$y=Ae^{\frac{x^2}{2}}$

Work Step by Step

We are given that $\dfrac{dy}{dx}=xy$ We will separate the variables to obtain: $\dfrac{dy}{y}=x dx$ Integrate to obtain: $\int \dfrac{dy}{y}=\int x dx$ This implies that $\ln |y|=\dfrac{x^2}{2}+C$ or, $e^{\ln |y|}=e^{\frac{x^2}{2}}+C$ Therefore, we have: $y=Ae^{\frac{x^2}{2}}$
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