Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 14 - Section 14.6 - Differential Equations and Applications - Exercises - Page 1068: 15

Answer

$y=2x$

Work Step by Step

We are given that $x \dfrac{dy}{dx}=y$ We will separate the variables to obtain: $\dfrac{\ dy}{y}=\dfrac{\ dx}{x}$ Integrate to obtain: $\int \dfrac{\ dy}{y}=\int \dfrac{\ dx}{x}$ This implies that $\ln |y|=\ln |x|+C$ After applying the initial conditions, $y=2$ when $x=1$, we get $C=\ln (2)$ Therefore, we have: $e^{\ln y}=e^{\ln x+\ln 2} \implies y=2x$
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