Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 14 - Section 14.6 - Differential Equations and Applications - Exercises - Page 1068: 3

Answer

$\dfrac{y^2}{2}=\dfrac{x^2}{2}+C$

Work Step by Step

We are given that $\dfrac{dy}{dx}=\dfrac{x}{y}$ We will separate the variables to obtain: $y \ dy=x \ dx$ Integrate to obtain: $\int y \ dy=\int x \ dx$ This implies that $\dfrac{y^2}{2}=\dfrac{x^2}{2}+C$
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