Answer
$ -\displaystyle \frac{1}{4x+10}+C$
Work Step by Step
Shortcut:
$\displaystyle \int(ax+b)^{n}dx=\frac{1}{a}\cdot\frac{(ax+b)^{n+1}}{n+1}+C$
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$a=2, b= 5, n=-2$
$\displaystyle \int(2x+5)^{3}dx=\frac{1}{2}\cdot\frac{(2x+5)^{-2+1}}{-2+1}+C$
$=\displaystyle \frac{(2x+5)^{-1}}{-2}+C$
$=-\displaystyle \frac{1}{4x+10}+C$
