Answer
$ \displaystyle \frac{(3x-5)^{4}}{12}+C$
Work Step by Step
Shortcut:
$\displaystyle \int(ax+b)^{n}dx=\frac{1}{a}\cdot\frac{(ax+b)^{n+1}}{n+1}+C$
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$a=3, b=-5, n=3$
$\displaystyle \int(3x-5)^{3}dx=\frac{1}{3}\cdot\frac{(3x-5)^{4}}{4}+C$
$=\displaystyle \frac{(3x-5)^{4}}{12}+C$
