Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 10 - Section 10.6 - Derivatives: Algebraic Viewpoint - Exercises - Page 768: 4

Answer

$f'(a)=\lim \limits_{h \to 0}-2$, which equals to $-2$. $f'(-1)=-2$

Work Step by Step

The algebraic derivative of a function can be described as: $f'(a)=\lim \limits_{h \to 0}\frac{f(a+h)-f(a)}{h}$ Here, $f(a)=-2a+4$ By substituting, we get: $\frac{-2(a+h)+4-(-2a+4)}{h}=\frac{-2a-2h+4+2a-4}{h}=\frac{-2h}{h}=-2$ $f'(a)=\lim \limits_{h \to 0}-2$, which equals to $-2$. $f'(-1)=-2$
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