Answer
$\displaystyle \lim_{t\rightarrow\infty}p(t)=100$
As their age increases, the percentage of children that learn to speak nears $100\%.$
Work Step by Step
When $t\rightarrow+\infty,$
$1-\displaystyle \frac{12200}{t^{4.48}}$ has the form $1-\displaystyle \frac{k}{Big} \rightarrow 1-0 =1$
So $100(1-\displaystyle \frac{12200}{t^{4.48}})\rightarrow 100(1)=100$
$\displaystyle \lim_{t\rightarrow\infty}p(t)=100$
As their age increases, the percentage of children that learn to speak, nears $100\%.$
